-3x^2+300x=0

Solution for -3x^2+300x=0 equation:

-3x^2+300x=0

a = -3; b = 300; c = 0;
Δ = b2-4ac
Δ = 3002-4·(-3)·0
Δ = 90000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{90000}=300$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(300)-300}{2*-3}=\frac{-600}{-6}
=+100
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(300)+300}{2*-3}=\frac{0}{-6}
=0
$